To find the equation of a line in slope-intercept form, which is given by the equation \( y = mx + b \) (where \( m \) is the slope and \( b \) is the y-intercept), we start by calculating the slope \( m \) using the two points given: \( (0, -2) \) and \( (1, 3) \).
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Calculate the Slope \( m \): The formula for the slope between two points \((x_1, y_1)\) and \((x_2, y_2)\) is: \[ m = \frac{y_2 - y_1}{x_2 - x_1} \]
Plugging in the coordinates of our points:
- \((x_1, y_1) = (0, -2)\)
- \((x_2, y_2) = (1, 3)\)
\[ m = \frac{3 - (-2)}{1 - 0} = \frac{3 + 2}{1} = \frac{5}{1} = 5 \]
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Use one of the points to find \( b \): We can use the point \( (0, -2) \) to find the y-intercept \( b \). When \( x = 0 \), \( y = b \).
Thus, from the point: \[ -2 = b \]
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Write the equation in slope-intercept form: Now that we have \( m = 5 \) and \( b = -2 \), we can write the equation of the line: \[ y = 5x - 2 \]
So the equation of the line in slope-intercept form is \( y = 5x - 2 \).