A graph shows the x and y axes ranging from negative 10 to 10 in unit increments. A line passes through five plotted points. The line passes through the following data points: left parenthesis negative 2 comma negative 3 right parenthesis, left parenthesis negative 1 comma negative 1 right parenthesis, left parenthesis 0 comma 1 right parenthesis, left parenthesis 1 comma 3 right parenthesis, and left parenthesis 2 comma 5 right parenthesis.

Analyze the graph and write a linear function in slope-intercept form.

y= ? x+ ?

1 answer

To determine the linear function in slope-intercept form (y = mx + b) based on the points provided, we can first identify the slope (m) using any two points provided on the line and then calculate the y-intercept (b).

Step 1: Calculate the slope (m)

The slope between two points \((x_1, y_1)\) and \((x_2, y_2)\) can be calculated using the formula:

\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]

Let's use the points \((-2, -3)\) and \((2, 5)\):

  • \((x_1, y_1) = (-2, -3)\)
  • \((x_2, y_2) = (2, 5)\)

Substituting into the slope formula:

\[ m = \frac{5 - (-3)}{2 - (-2)} = \frac{5 + 3}{2 + 2} = \frac{8}{4} = 2 \]

Step 2: Calculate the y-intercept (b)

We can use the slope \(m = 2\) and one of the points to find the y-intercept \(b\). We'll use the point \((0, 1)\):

The slope-intercept form is:

\[ y = mx + b \]

Substituting the point \((0, 1)\) into the equation:

\[ 1 = 2(0) + b \implies b = 1 \]

Final Equation

Now that we have both \(m\) and \(b\), we can write the equation of the line:

\[ y = 2x + 1 \]

So, the linear function in slope-intercept form is:

\[ y = 2x + 1 \]