To find the distance between the two points using the Pythagorean Theorem, we can treat the distance as the hypotenuse of a right triangle, where the legs are the differences in the x-coordinates and y-coordinates.
The two points are:
- Point A: \((-2, -1)\)
- Point B: \((2, 4)\)
-
Calculate the difference in the x-coordinates: \[ \Delta x = x_2 - x_1 = 2 - (-2) = 2 + 2 = 4 \]
-
Calculate the difference in the y-coordinates: \[ \Delta y = y_2 - y_1 = 4 - (-1) = 4 + 1 = 5 \]
-
Apply the Pythagorean theorem to find the distance \(d\): \[ d = \sqrt{(\Delta x)^2 + (\Delta y)^2} = \sqrt{(4)^2 + (5)^2} = \sqrt{16 + 25} = \sqrt{41} \]
-
Evaluate \(\sqrt{41}\): \[ \sqrt{41} \approx 6.4 \]
So the distance between the two points \((-2, -1)\) and \((2, 4)\) is approximately 6.4 when rounded to the nearest hundredth.
Now, for the second set of points:
- Point A: \((2, -3)\)
- Point B: \((5, 5)\)
-
Calculate the difference in the x-coordinates: \[ \Delta x = 5 - 2 = 3 \]
-
Calculate the difference in the y-coordinates: \[ \Delta y = 5 - (-3) = 5 + 3 = 8 \]
-
Apply the Pythagorean theorem to find the distance \(d\): \[ d = \sqrt{(3)^2 + (8)^2} = \sqrt{9 + 64} = \sqrt{73} \]
-
Evaluate \(\sqrt{73}\): \[ \sqrt{73} \approx 8.54 \]
So the distance between the points \((2, -3)\) and \((5, 5)\) is approximately 8.54 when rounded to the nearest hundredth.