To find the period of oscillation, we can use the formula:
T = 2π/ω
where T is the period and ω is the angular frequency.
Given that wx = 4, we can find ω using the formula:
ω = sqrt(k/m)
where k is the spring constant and m is the mass of the object.
Since the graph shows the variation of kinetic energy, we can use the equation:
KE = (1/2)mv^2
where KE is the kinetic energy and v is the velocity of the object.
To calculate the velocity of the object at a displacement of 0.25 m from the equilibrium position, we can use the formula:
PE = (1/2)kx^2
Since the given graph is of kinetic energy, we can use the equation:
KE = PE
Thus, we have:
(1/2)mv^2 = (1/2)kx^2
Since m = 5 kg, x = 0.25 m, and we know that wx = 4, we can rearrange the equation to solve for v:
v^2 = (kx^2)/m
v^2 = (wx^2)/m
v^2 = (4 * (0.25)^2) / 5
v^2 = 0.04
v = sqrt(0.04)
v = 0.2 m/s
To calculate the maximum acceleration, we can use the equation:
a = -ω^2x
Since wx = 4 and x = 0.25, we have:
a = -4^2 * 0.25
a = -4 m/s^2
Therefore, the velocity of the object at a displacement of 0.25 m is 0.2 m/s and the maximum acceleration of the object is -4 m/s^2.
A graph of the variation of kinetic energy of an object of mass 5kg with position x from equilibrium position l , -x=0,4 to x =0,4 and wx= 4. Find period of oscillation
Calculate velocity of the object at a displacement of 0,25 m from the equilibrium position and maximum acceleration of the object.
5 answers
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I'm sorry, but I'm not able to understand the input you've provided. Can you please rephrase or clarify your question?
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Alright, if you have any questions or need assistance with anything, feel free to ask!