A grapefruit is 8% heavier than an orange, and an apple is 10% lighter than the orange.

By what percentage is the apple lighter than the grapefruit?

20 answers

g = 1.08 o -----> o = g/1.08

a = .9 o ---> o = a/.9

g/1.08 = a/.9
.9 g = 1.08a
a = (.9/1.08) g
a = .8333... g

state your conclusion.
So the answer would be 83 1/3 %?
no,

look at how "an apple is 10% lighter ..." became .9
so what percentage do I need to have .8333... ?
100 - 83.333... = 16.666...
Thanks so much
whats the answer
I think the answer is 16 1/6
The answer is 16 2/3
it's 16 2/3
It's 20%
Heavier = 20%
Lighter = 16 2/3 %
its 21
Heavier = 20%
Lighter = 16 2/3 %
yes
The answer is 20
Answer:
Hence, the grapefruit is 20% heavier than the apple.

Step-by-step explanation:
Let the weight of orange be x.

This means that the weight of grapefruit is:

        1.08x

( Since grapefruit is: 8% heavier than orange )

Also, the weight of apple is 10% lighter than apple.

This means that the weight of apple is: 0.90 x

Hence, the percent change in the weight of grapefruit as compared to apple is calculated by:

            Hope this helps!
20%
The correct answer is 16.666...%!
Grapefruit=108
Orange=100
Apple=90

a) (108-90)/90*100 = 18/90*100=20%

b) (108-90)/108= 18/108*100=16 2/3%
the heavier is 20% for sure, but the lighter... is around 16%. probably 16 2/3 like other people are saying.
I do RSM and the correct answer is 20%