Vo = 31.1m/s[37o]
Xo = 31.1*Cos37 = 24.84 m/s.
Yo = 31.1*sin37 = 18.72 m/s.
Y = Yo + g*Tr = 0
18.72 - 9.8*Tr = 0
9.8Tr = 18.72
Tr = 1.91 s. = Rise time.
Y^2 = Yo^2 + 2g*h = 0
h=-Yo^2/2g = -(18.72)^2/-19.6 = 17.88 m
= Max. ht.
0.5g*t^2 = 17.88 - 5.50
4.9t^2 = 12.38
t^2 = 2.53
t = 1.59 s. = Fall time(Tf).
a. Tr+Tf = 1.91 + 1.59 = 3.50 s. = Time in air.
b. D = Xo*(Tr+Tf) = 24.84 * 3.50 = 86.9 m.
c. Y = Yo + g*Tf = 0 + 9.8*1.59 = 15.58 m/s. = Ver. component of final velocity.
V = sqrt(Xo^2+Y^2)
A golfer, standing on a fairway, hits a shot to a green that is elevated 5.50 m above the point where she is standing. The ball leaves her club at an angle of 37.0° above the ground, with a speed of 31.1 m/s.
Find the time that the ball is in the air before it hits the green.
How far did the ball travel horizontally?
Determine the ball's speed right before it hits the green.
1 answer