A golfer played 8 rounds on a tournament

Question

course with the following scores (par is the
expected score for a round; negative numbers represent
the number of strokes under par for the round,
and positive numbers represent the number of strokes
over par for the round):+5,-2,+3,-1,-3,+6,+2,-7
The golfer played 2 more rounds, ending with an
even par total for the 10 rounds. Her score for the last
round was 7 more than her score on the next-to-last
round. What scores did the golfer have on the last two
rounds?

Answer 1

I would do this.
Add the + and - scores for the 8 games played. I get +3. Since the 10 games were played with even par, that means that the last two games had scores that add to +3.
Let L = score of last game.
and N = score of next to last game.
We know L + N = +3 and the problem states that L = N+7.
Two unknowns. Two equations. Solve the two equations. Check my thinking.

Answer 2

thats just it i can get that far but i can not solve equations with 2 unknows

Answer 3

and if the first part he got +3 and par is 0 shouldnt the last two equal -3

Answer 4

L + N must = +3 to bring the mean to par (0).

Substitute N + 7 for L in the first equation and solve for N. Put that value in the second equation to find L. Put both values in the first equation to check.

I hope this helps a little more. Thanks for asking.

Answer 5

i still can not figure it out i get 2n+7=3 but if you subtract 7 and then divide by 2 you do not get a whole number so it cant be right