A golfer is enjoying a day out on the links. What maximum height will a 345m drive reach if it is launched at an angle of 21 degrees to the ground? the acceleration due to gravity is 9.81m/s^2

Answer 1

Given the distance and angle of elevation,
the velocity with which the ball left the club face derives from

d = V^2(sin(µ))/g

which then allows the maximum height reached to be found from

h = [V^2(sin^2(µ))]/2g

Answer 2

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