initial KE+initial PE=finalKE+finalPE
1/2 m 19.4^2 + 0 =1/2 m v^2 +mg*3.10
m divides out, solve for v
A golfer hits a shot to a green that is elevated 3.10 m above the point where the ball is struck. The ball leaves the club at a speed of 19.4 m/s at an angle of 33.0˚ above the horizontal. It rises to its maximum height and then falls down to the green. Ignoring air resistance, find the speed of the ball just before it lands.
2 answers
i can't figure that out i got the wrong answer