A golfer hits a shot to a green that is elevated 3.0 m above the point where the ball is struck. The ball leaves the club at a speed of 19.4 m/s at an angle of 45.0˚ above the horizontal. It rises to its maximum height and then falls down to the green. Ignoring air resistance, find the speed of the ball just before it lands.

2 answers

consider energy:

initial PE+initial KE= finalPE+finalKE
0+1/2 m 19.4^2=mg*3=1/2 m vf^2

solve for Vfinal
13.6