To determine how far the ball travels when it hits the ground, we need to solve for \(x\) when \(h(x) = 0\) in the equation \(h(x) = -\frac{1}{25}x(x - 45)\).
Setting \(h(x) = 0\):
\[ 0 = -\frac{1}{25}x(x - 45) \]
We can multiply both sides by -25 to simplify:
\[ 0 = x(x - 45) \]
This equation factors to:
\[ 0 = x(x - 45) \]
Setting each factor to zero gives us the solutions:
- \(x = 0\)
- \(x - 45 = 0 \implies x = 45\)
Thus, the ball will hit the ground when it has traveled \(0\) yards (the initial position) or \(45\) yards.
Since the hole is \(55\) yards away, if the ball hits the ground after \(45\) yards, we can find the additional distance it needs to roll to reach the hole:
\[ \text{Distance to hole} = 55 - 45 = 10 \text{ yards} \]
Therefore, the ball will hit the ground after it has traveled \(45\) yards, and it will need to roll an additional \(10\) yards to reach the hole.
The correct response is:
The ball will hit the ground after it has traveled 45 yards. It will need to roll an additional 10 yards to reach the hole.