A golf ball with a mass of 0.080kg initially at rest is given a speed of 50 m.s-1 when it is struck by a golf club. A) If the club and ball are in contact for 1.5 millisecond (0.0015 seconds), What average force acts on the ball? B) What impulse was delivered? c) What was the change in momentum of the ball?

Answer 1

a = (V-Vo)/t. V = 50 m/s, Vo = 0, a = ?.

A. F = M*a.

B. Impulse = M*t.

C. Momentum ch. = M*V-M*Vo.

C.

Answer 2

Correction: B. Impulse = F*t.