A golf ball leaves a tee at 60n/s and strikes the ground 200m away. At what two angles with the horizontal could it have begin its flight? Find the timed of flight and maximum attitude in each case.

Answer 1

let's use m/s instead of n/s

the range equation is ... R = u^2 * sin(2θ) / g
... u is the launch velocity, and θ is the launch angle

solving for θ ... sin(2θ) = R * g / u^2
... there are two solutions

find the two possible vertical velocities ... u * sin(θ)

the flight times (t) are ... t = [2 * u * sin(θ)] / g

the max altitudes are ... 1/2 * g * t^2

Answer 2

What's the answer? It's for college