A golf ball is thrown at an angle of 37 degree with horizontal with initial speed of 50 m/s. what is the maximum horizontal distance???
3 answers
L=vₒ²sin2α/g=50²•sin74º/9.8=245.2 m
this question is multiple choice there are choices and this answer is not among them :(
Upward motion (from the start point to the highest point)
v=v(0y)-gt ,
v=0
t= v(0y)/g=v(0) •sinα/g
the horizontal range is
L=2•v(x) •t=2•v(0) •cosα•v(0) •sinα/g= =v²(0) •sin2 α/g.
This is correct answer (both formula and calculation).
Show your set of answers.
v=v(0y)-gt ,
v=0
t= v(0y)/g=v(0) •sinα/g
the horizontal range is
L=2•v(x) •t=2•v(0) •cosα•v(0) •sinα/g= =v²(0) •sin2 α/g.
This is correct answer (both formula and calculation).
Show your set of answers.