Asked by Michael
A golf ball is hit with an initial velocity of 50 m/s at an angle of 45 degrees with the horizontal. How far will it travel horizontally before it hits the ground?
Answers
Answered by
drwls
For initial velocity V and a launch angle A, the horizontal distance travelled is
X = 2 sin A cos A (V^2/g)
=(V^2/g) sin 2A
In this case, sin 2A = 1.
X = 2 sin A cos A (V^2/g)
=(V^2/g) sin 2A
In this case, sin 2A = 1.
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