a golf ball is hit at an angle of 45 degrees with the horizontal. if the initial velocity of the ball is 52m/s , how far will it travel horizontally before striking the ground?

Answer 1

First the vertical problem
Vi = initial speed up = 52 sin 45
= 36.8 m/s
H = 0 + Vi t - 4.9 t^2
0 = 0 +36.8 t - 4.9 t^2
t = 0 or 7.5 seconds
so 7.5 seconds in air

now horizontal problem
u = 52 cos 45 = 36.8 m/s forever
d = u t = 36.8 * 7.5

Answer 2

A golfer hits a ball and gives it an intial velocity of 40 m/s, at an angle 30° above the horizontal .
A. How long does the ball stay in the air ?

Answer 3

20s

Answer 4

20