A golf ball is dropped from rest from a height of 8.30 m. It hits the pavement, then bounces back up, rising just 5.00 m before falling back down again. A boy then catches the ball when it is 1.10 m above the pavement. Ignoring air resistance, calculate the total amount of time that the ball is in the air, from drop to catch.

1 answer

Basic kinetmatics stuff. Use
s = ½at² to find the time to fall s = 8.3m
Then use kinematics to find the time to fall 5.0m
(It's actually rising, but time to fall = time to rise, and fall time is easier to calculate (no initial v)!)
Then use kinematics to find the time to fall (5.0m - 1.1m).
Add the three times for your answer.

btw what school u go to