k = 1.05 W/(m C)
l = 6*10^-3 m
(Th - Tc) = 27 C
A = 3.50 m^2
Do the numbers again. You should not get 13 (Watts) It is much more than that. Did you remember to express the thickness l in meters? What did you use for k ?
A glass window pane has an area of 3.50 m2 and a thickness of 0.600 cm. If the temperature difference between its surfaces is 27.0°C, what is the rate of energy transfer by conduction through the window?
I tried using the formula P=ka[(th-Tc)/l] my answer was thirteen but this is not right, help please.
2 answers
21