A glass vessel is completely filled with 60cm3 of mercury of 18°c the temperature of glass increase to 60°c the linear cofficient of expansion is 9×10 and volumetric is 180×10 CALCULATE absolutely expansion of mercury and apparent expansion of mercury

Answer 1

To calculate the absolute expansion of mercury, we need to use the formula:

ΔV = V0 * β_m * ΔT

Where:
ΔV = change in volume of mercury
V0 = initial volume of mercury (60 cm^3)
β_m = volumetric coefficient of expansion of mercury (180x10^-6 / °C)
ΔT = change in temperature (60°C - 18°C = 42°C)

ΔV = 60 cm^3 * 180x10^-6 / °C * 42°C
ΔV = 60 cm^3 * 0.00018 / °C * 42°C
ΔV = 0.4536 cm^3

Therefore, the absolute expansion of mercury is 0.4536 cm^3.

To calculate the apparent expansion of mercury, we need to use the formula:

ΔV_apparent = ΔV - α_g * V0 * ΔT

Where:
ΔV_apparent = apparent expansion of mercury
ΔV = absolute expansion of mercury (0.4536 cm^3)
α_g = linear coefficient of expansion of glass (9x10^-6 / °C)
V0 = initial volume of mercury (60 cm^3)
ΔT = change in temperature (60°C - 18°C = 42°C)

ΔV_apparent = 0.4536 cm^3 - 9x10^-6 / °C * 60 cm^3 * 42°C
ΔV_apparent = 0.4536 cm^3 - 0.000027 * 60 cm^3 * 42°C
ΔV_apparent = 0.4536 cm^3 - 0.0684 cm^3
ΔV_apparent = 0.3852 cm^3

Therefore, the apparent expansion of mercury is 0.3852 cm^3.