To determine how much mercury will be above the mark when the glass and its contents are heated to 40°C, we first need to find the expansion coefficient of the mercury and the glass.
The coefficient of volume expansion for mercury is 180x10^(-6) ¹/°C, and the glass's coefficient is 27x10^(-6) ¹/°C.
Now, let's find the volume expansion for both the mercury and the glass.
ΔV_Mercury = Initial volume x coefficient x ΔT
ΔV_Mercury = 60 cm³ x 180x10^(-6) ¹/°C x (40°C - 20°C)
ΔV_Mercury = 60 cm³ x 180x10^(-6) ¹/°C x 20°C
ΔV_Mercury = 0.00324 cm³
Let us assume the initial volume of the flask is V cm³ (up to the mark). Now, we will find the volume expansion for the glass (flask).
ΔV_Glass = Initial volume x coefficient x ΔT
ΔV_Glass = V cm³ x 27x10^(-6) ¹/°C x (40°C - 20°C)
ΔV_Glass = V cm³ x 27x10^(-6) ¹/°C x 20°C
ΔV_Glass = V cm³ x 0.00054 cm³/cm³
Since we are only interested in the change in mercury's level, we can set up the following equation:
0.00324 cm³ - V cm³ x 0.00054 cm³/cm³ = ΔV_AboveMark
However, we don't have the initial volume of the flask, V. In real-world scenarios, the volume of the flask is usually much larger than the volume of mercury filled into it (60 cm³). Considering this, the expansion of the glass will have a much smaller impact compared to the expansion of the mercury.
Thus, we can approximate the change in mercury's level with the expansion of the mercury:
ΔV_AboveMark ≈ ΔV_Mercury = 0.00324 cm³
So, approximately 0.00324 cm³ of mercury will be above the mark when the flask and its content are heated to 40°C.
A glass is filled to the mark with60cm³of mercury at 20°C if the flask and its content are heated at 40°C how much Mercury will be above the mark
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