To solve this problem, we can break down the initial velocity of the rock into its horizontal and vertical components.
The horizontal component of the velocity is given by: Vx = 30 * cos(30) = 26.0 m/s
The vertical component of the velocity is given by: Vy = 30 * sin(30) = 15.0 m/s
Next, we can calculate the time it takes for the rock to reach the ground by using the vertical motion equation:
h = Vy * t + (1/2) * g * t^2
50 = 15 * t + (1/2) * 9.81 * t^2
Solving for t, we get t = 3.19 seconds
Finally, we can calculate the horizontal distance the rock travels by using the horizontal motion equation:
D = Vx * t
D = 26.0 * 3.19
D = 52.3 meters
Therefore, the rock will land 52.3 meters from the base of the building.
A girl standing on top of a roof Throws a rock at 30m/s at an angle 30 degrees below the horizontal is the roof top is 50m high how far from the base of the building with the rock land The answer is 52.3
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