a girl standing appriteexerts apressure of 15000N/m2 on the floor givn tht the ttl area of cntact of shoes and floor is 0.02m2.determine her mass.determine the pressure she would exert on the floor if she stood on one foot

Answer 1

To determine the girl's mass, we can use the formula:

Pressure (P) = Force (F) / Area (A)

Given:

Pressure on the floor (P) = 15000 N/m^2
Area of contact (A) = 0.02 m^2

Rearranging the formula, we can solve for the force:

Force (F) = Pressure (P) * Area (A)
F = 15000 N/m^2 * 0.02 m^2
F = 300 N

Therefore, the girl's mass is 300 kg. (Using the formula F = m * g, where g is the acceleration due to gravity, which is approximately 9.8 m/s^2)

To determine the pressure she would exert on the floor if she stood on one foot, the force would remain the same (300 N). However, the area of contact would be halved since she is now standing on one foot.

Area of contact (new) = 0.02 m^2 / 2
Area of contact (new) = 0.01 m^2

Using the formula P = F/A, where P is the pressure:

Pressure (new) = 300 N / 0.01 m^2
Pressure (new) = 30000 N/m^2

Therefore, the pressure the girl would exert on the floor if she stood on one foot is 30000 N/m^2.