A girl sits on a tire swing that is attached with a rope that is 2.10 m in length. Her dad pushes her with a speed of 2.5 m/s. If the centripetal force is 88.0 N, what is the girl’s mass?

Answer 1

To find the girl's mass, we can use the formula for centripetal force:

F_c = (m * v^2) / r

Where:
F_c = centripetal force (88.0 N)
m = mass of the girl
v = speed of the girl (2.5 m/s)
r = radius of the tire swing (2.10 m)

Substitute the given values into the formula:

88.0 = (m * (2.5)^2) / 2.10

Simplify:

88.0 = (m * 6.25) / 2.10

88.0 * 2.10 = m * 6.25

184.8 = 6.25m

Divide by 6.25 to solve for m:

m = 29.568 kg

Therefore, the girl's mass is 29.568 kg.