a girl on a swing 2m above the ground at her highest point and 1m above the ground at her lowest point. what is the girls maximum speed?

Answer 1

If I understand conservation of energy correctly, if her weight is mg, then the loss of PE going from 2m to 1m is mg Joules.

So, since that is converted to KE, we have

mg = 1/2 mv^2
2g = v^2
v = √19.6 m/s

Answer 2

Loss in P.E = Gain in K.E
mgh = 1/2mv^2
g(1) = 1/2v^2
2g = v^2
v = √19.6 = 4.427 m/s (Answered)

Answer 3

?? whats the Answers....