A girl of mass 48.0 kg is rescued from a building fire by leaping into a firefighters net. The window from which she leapt was 12.0 m above the net.She lands in the net so that she is brought to complete stop in 0.45 s.During this interval what is her change in momentum?

Answer 1

mgh = 1/2 mv^2
So, v^2 = 9.81*12*2 = 235.44
her momentum upon impact was p = mv = 48 * 15.34 = 736.51 kg-m/s
So, ∆p = -736.51 kg-m/s
maybe you want the rate of change of p. In that case, just divide by 0.45s

Answer 2

It was very helpful

Answer 3

Good

Answer 4

Solution is not right

Answer 5

Good

Answer 6

Wrong solution . your answer is wrong

Answer 7

I think its change in momentum as girl was leaping from height so the initial velocity is zero and final velocity simply can be derived from equation of motion.