a girl is using a rope to pull a box that weighs 300N across a level surface with constant velocity. the rope makes an angle of 30 degree above the horizontal and the tension in the rope is 100N. What is the normal force of the floor on the box?

Answer 1

M*g = 300 N
T = 100N[30o]

Fn = M*g - T*sin A = 300 - 100*sin30

Answer 2

317.10

Answer 3

250N

Answer 4

Wrong

Answer 5

Fn=W-T,but the rope make an angle so Tsin30
Fn=W-Tsin30
Fn= 300-(100×0.5)
Fn=250N