a geometry teacher has a set of 60 plastic pentagons and octagons. she happened to notice that all the figures together have a total of 354 sides. how many of each shape are there.

1 answer

Let \( p \) be the number of pentagons and \( o \) be the number of octagons. We can set up the following system of equations based on the information provided:

  1. The total number of shapes is 60: \[ p + o = 60 \]

  2. The total number of sides is 354: \[ 5p + 8o = 354 \]

We can solve this system of equations step by step.

First, from the first equation, we can express \( o \) in terms of \( p \): \[ o = 60 - p \]

Next, we substitute this expression for \( o \) into the second equation: \[ 5p + 8(60 - p) = 354 \] Expanding this gives: \[ 5p + 480 - 8p = 354 \] Combining like terms, we have: \[ -3p + 480 = 354 \] Subtracting 480 from both sides: \[ -3p = 354 - 480 \] \[ -3p = -126 \] Dividing by -3: \[ p = 42 \]

Now that we have \( p \), we can find \( o \) using the expression we found earlier: \[ o = 60 - p = 60 - 42 = 18 \]

Thus, the teacher has \( \boxed{42} \) pentagons and \( \boxed{18} \) octagons.

Let's verify our solution:

  • The total number of shapes is \( 42 + 18 = 60 \) (correct).
  • The total number of sides is \( 5(42) + 8(18) = 210 + 144 = 354 \) (correct).

Everything checks out!

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