Asked by Rose
A general reaction written as 1A + 2B --> C + 2D is studied and yields the following data:
Expt (A). (B) initial (C)/t
1. 0.150. 0.150. 8.00 x10^-3
2. 0.150. 0.300. 1.60 x10^-2
3. 0.300. 0.150. 8.00 x10^-3
What is the order of the reaction with respect to B?
What is the order of the reaction with respect to A?
Determine the initial rate of B consumption (delta(B)/delta t) for the first trial?
Expt (A). (B) initial (C)/t
1. 0.150. 0.150. 8.00 x10^-3
2. 0.150. 0.300. 1.60 x10^-2
3. 0.300. 0.150. 8.00 x10^-3
What is the order of the reaction with respect to B?
What is the order of the reaction with respect to A?
Determine the initial rate of B consumption (delta(B)/delta t) for the first trial?
Answers
Answered by
DrBob222
rate exp 2 = k1*(A)^x(B)^y
--------------------------
rate exp 1 = k1*(A)^x(B)^y
Now plug in values for exp 1 and exp 2. That will give you
1.60E-2 = k1*(0.300)^x*(0.0.150)^y
--------=-------------------------8.00E-3 = k1*(0.15o)^x(0.150)^y
k1 cancels.
0.150)^y cancels and you are left
2 = (0.300)^x/(0.150)^y and becomes
2 = 2^x so x must be 1 and that's the order of B.
Can you handle the rest of it. This is how you do it.
--------------------------
rate exp 1 = k1*(A)^x(B)^y
Now plug in values for exp 1 and exp 2. That will give you
1.60E-2 = k1*(0.300)^x*(0.0.150)^y
--------=-------------------------8.00E-3 = k1*(0.15o)^x(0.150)^y
k1 cancels.
0.150)^y cancels and you are left
2 = (0.300)^x/(0.150)^y and becomes
2 = 2^x so x must be 1 and that's the order of B.
Can you handle the rest of it. This is how you do it.
Answered by
hah
a7a I can't
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.