A gas tank is filled with gas to a pressure of 60.0 PSI at 25°C what will the pressure of gas in the tank is warmed to 35°C

Answer 1

Before we calculate the new pressure of the gas in the tank at 35°C, we need to convert the temperatures from Celsius to Kelvin.

T1 = 25°C + 273.15 = 298.15 K
T2 = 35°C + 273.15 = 308.15 K

Now we can use the ideal gas law equation:
P1/T1 = P2/T2

where:
P1 = 60.0 PSI
T1 = 298.15 K
P2 = unknown
T2 = 308.15 K

Now we can solve for P2:
60.0 PSI / 298.15 K = P2 / 308.15 K

P2 = (60.0 PSI * 308.15 K) / 298.15 K
P2 = 62.074 PSI

Therefore, the pressure of the gas in the tank when warmed to 35°C is approximately 62.1 PSI.