In the given piecewise function, we have:
- For \( x < 10 \), \( f(x) = 2.5x \)
- For \( x \geq 10 \), \( f(x) = 2.25x \)
At \( x = 10 \), we need to determine the value of the function from both sides.
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When \( x = 10 \), using the second part of the piecewise function for \( x \geq 10 \): \[ f(10) = 2.25 \times 10 = 22.5 \]
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Because we have a change in the function formula at \( x = 10 \), it is defined at that point, and the value from the first part, \( f(x) = 2.5x \), for \( x < 10 \): \[ f(10) \text{ (for the first part)} = 2.5 \times 10 = 25 \]
Since the first part is not applicable at \( x = 10\) (as that is the threshold for the second piece), the value at \( x = 10 \) will be determined by \( f(x) = 2.25x \), which gives \( 22.5\).
Since the definition of the function changes at \( x = 10 \), and from the first piece \( f(x) = 2.5x \) does not included \( (10, 25) \), this point will have an open circle.
Thus, the point that would have an open circle is:
(10, 25)