A gas of unknown molecular mass was allowed to effuse through a small opening under constant-pressure conditions. It required 52 s for 1.0 L of the gas to effuse. Under identical experimental conditions it required 24 s for 1.0 L of O2 gas to effuse. Calculate the molar mass of the unknown gas. (Remember that the faster the rate of effusion, the shorter the time required for effusion of 1.0 L; that is, rate and time are inversely proportional.)

Question

DrBob222 · Answer

(rateO2/rateunk) = sqrt(Munk/MO2) M = molar mass unk = unknown

Jennifer · Answer

thank you!

Pitsa · Answer

Did this solution ever work for you? I tried it on my homework but it didn't work. Thanks