A gas occupies 560.0 mL at 285 K. To what temperature must the gas be lowered if it is to occupy 250.0 mL? Assume that the pressure remains constant.

Answer 1

Assuming the gas is ideal, we use Charles' Law to relate the relationship between Temperature & Volume of gas:
V1/T1 = V2/T2
where:
T1 = initial temperature of gas (in K)
T2 = final temperature of gas (in K)
V1 = initial volume of gas
V2 = final volume of gas
substituting,
(560)/(285) = V2/(250)
V2 = (560*250)/285
V2 = ? (units in mL)

hope this helps~ :)

Answer 2

127

Answer 3

Nothing