P1V1= P2V2
Let P1= P1
(550mL)(P1)= (V2)(22P1)
P1 Cancels Out.
V2 = 550/22 mL
A gas has a volume of V1 = 550 mL. If the
temperature is held constant, what volume
would the gas occupy if P2 = 22 P1?
1 answer
temperature is held constant, what volume
would the gas occupy if P2 = 22 P1?
1 answer