(V1/T1) = (V2/T2)
Remember T must be in kelvin.
A gas has a volume of 590mL at a temperature of -55.0C What volume will the gas occupy at 30.0C
Can someone help me?
5 answers
dont understand
I gave you the equation. All you must do is substitute the numbers into the equation.
V1 = 590 mL
T1 = -55C = 273+(-55) = ? Kelvin
V2 = ? solve for this.
T2 = 30 C = 273 + 30 = ? Kelvin
V1 = 590 mL
T1 = -55C = 273+(-55) = ? Kelvin
V2 = ? solve for this.
T2 = 30 C = 273 + 30 = ? Kelvin
Here is the answer you guys ^v^
V1/T1 = V2/T2
V1 = 590 mL
T1 = -55 + 273 = 218 K
T2 = 30 + 273 = 303 K
590/218 = V2/303
V2 = 303*590 / 218
V2 = 820.05 mL
V1/T1 = V2/T2
V1 = 590 mL
T1 = -55 + 273 = 218 K
T2 = 30 + 273 = 303 K
590/218 = V2/303
V2 = 303*590 / 218
V2 = 820.05 mL
how did you get 273?