A gas has a pressure of 0.370 atm at 50.0 °C. What is the pressure at 22 °C, assuming volume remains constant?

Answer 1

Assuming the gas is ideal, we use Gay-Lussac's Law to relate the relationship between Temperature & Pressure of gas:
P1/T1 = P2/T2
where:
T1 = initial temperature of gas (in K)
T2 = final temperature of gas (in K)
P1 = initial pressure of gas
P2 = final pressure of gas
*note that to convert Celsius to Kelvin, we just add 273.
substituting,
(0.370)/(50+273) = P2/(22+273)
P2 = (0.370)(323)/295
P2 = ?

now solve for P2. units in atm.
hope this helps~ :)