To calculate the work done by the gardener, we can use the formula for work:
\[ \text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) \]
where:
- Force is the applied force (in Newtons),
- Distance is the distance over which the force is applied (in meters),
- \(\theta\) is the angle between the force and the direction of movement. Assuming the gardener is pushing the wheelbarrow horizontally, \(\theta\) is 0 degrees, and \(\cos(0) = 1\).
In this case:
- Force = 94.5 N
- Distance = 53 m
Now we can calculate the work done:
\[ \text{Work} = 94.5 , \text{N} \times 53 , \text{m} \times \cos(0) \] \[ \text{Work} = 94.5 , \text{N} \times 53 , \text{m} \times 1 \] \[ \text{Work} = 94.5 , \text{N} \times 53 , \text{m} = 5,003.5 , \text{J} \]
Therefore, the work done by the gardener is approximately 5,003.5 Joules.
Based on the options provided, none of them accurately reflect the calculated work. However, if we consider possible rounding or approximations in the scenarios provided, the closest could be:
\[ 5,008.5 N \]
It may need an explanation or an adjustment, as this isn't the standard way to present work, but if constrained to those options, that's the direction it would point. Nonetheless, the correct calculation gives around 5,003.5 Joules.
Please check to see if there might be a miscommunication in units since "N" represents force, not work.