A gardener holds a hose 0.75 m above the ground such that water shoots out horizontally and hits the ground at a point 2 m away. What is the speed with which the water leaves the hose?
7 answers
123.56
Solution please?
how long does it take to fall 0.75m?
4.9t^2 = 0.75
the speed is 2/t m/s
I don't think the above answer is correct.
4.9t^2 = 0.75
the speed is 2/t m/s
I don't think the above answer is correct.
I calculated it as 5.11 m/s is that right?
given
dy= -0.75m
dx= 2m
g= 9.8 m/s²
sol
vx
formula dx=vxt
dx/t=vxt/t
vx=dx/t
solve for t
form; square root of 2dy/g
t= square root of 2(-0.75m)/-9.8m/s²
t=0.39s
vx= dx/t
v= 2m/39
answer= 5.13 m/s
dy= -0.75m
dx= 2m
g= 9.8 m/s²
sol
vx
formula dx=vxt
dx/t=vxt/t
vx=dx/t
solve for t
form; square root of 2dy/g
t= square root of 2(-0.75m)/-9.8m/s²
t=0.39s
vx= dx/t
v= 2m/39
answer= 5.13 m/s
pakyu
suck