To determine which points are viable combinations that meet the designer's production goal represented by the inequality \(25x + 15y \geq 200\), we can test each point one by one by substituting the values of \(x\) and \(y\) into the inequality.
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Point (2, 10): \[ 25(2) + 15(10) = 50 + 150 = 200 \] Since \(200 \geq 200\) is true, \((2, 10)\) is a viable solution.
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Point (3, 8): \[ 25(3) + 15(8) = 75 + 120 = 195 \] Since \(195 \geq 200\) is false, \((3, 8)\) is not a viable solution.
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Point (4, 6): \[ 25(4) + 15(6) = 100 + 90 = 190 \] Since \(190 \geq 200\) is false, \((4, 6)\) is not a viable solution.
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Point (6, 2): \[ 25(6) + 15(2) = 150 + 30 = 180 \] Since \(180 \geq 200\) is false, \((6, 2)\) is not a viable solution.
Summary: The only viable combination that meets the designer's production goal is \((2, 10)\).