To determine which points meet the designer's production goal represented by the inequality \( 25x + 15y \geq 200 \), we will substitute each point into the inequality and check if it satisfies the condition.
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Point (2, 10): \[ 25(2) + 15(10) = 50 + 150 = 200 \] Since \( 200 \geq 200 \) is true, (2, 10) is a viable solution.
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Point (3, 8): \[ 25(3) + 15(8) = 75 + 120 = 195 \] Since \( 195 \geq 200 \) is false, (3, 8) is not a viable solution.
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Point (4, 6): \[ 25(4) + 15(6) = 100 + 90 = 190 \] Since \( 190 \geq 200 \) is false, (4, 6) is not a viable solution.
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Point (6, 2): \[ 25(6) + 15(2) = 150 + 30 = 180 \] Since \( 180 \geq 200 \) is false, (6, 2) is not a viable solution.
After checking all the points, the only viable combination that meets the designer's production goal is (2, 10).
Thus, the answer is:
- Viable points: (2, 10)
- Non-viable points: (3, 8), (4, 6), (6, 2)