To find the probability of getting an even number on both the spinner and the number cube, we first need to identify the even numbers on each.
Spinner (numbers 1–5):
The even numbers are:
- 2
- 4
Total even numbers on the spinner: 2
Total numbers on the spinner: 5
Probability of getting an even number on the spinner: \[ P(\text{even on spinner}) = \frac{\text{number of even outcomes}}{\text{total outcomes}} = \frac{2}{5} \]
Number Cube (numbers 1–6):
The even numbers are:
- 2
- 4
- 6
Total even numbers on the number cube: 3
Total numbers on the number cube: 6
Probability of getting an even number on the number cube: \[ P(\text{even on cube}) = \frac{\text{number of even outcomes}}{\text{total outcomes}} = \frac{3}{6} = \frac{1}{2} \]
Combined Probability:
To find the probability of both events happening (getting an even number on both the spinner and the number cube), we multiply their individual probabilities: \[ P(\text{even on both}) = P(\text{even on spinner}) \times P(\text{even on cube}) = \frac{2}{5} \times \frac{1}{2} \] \[ P(\text{even on both}) = \frac{2 \times 1}{5 \times 2} = \frac{2}{10} = \frac{1}{5} \]
Thus, the probability of getting an even number on both the spinner and the number cube is \(\frac{1}{5}\).
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