Reverse the Cd half cell and add to the Cu half cell as written. Calculate Eo cell.
Then dG = -nFEcell.
n is 2 and F is 96,485.
A galvanic cell is composed of these two half-cells, with the standard reduction potentials shown:
Cu2+(aq) + 2 e- ---->Cu(s)
+0.34volt
Cd2+(aq) + 2 e- ---->Cd(s)
-0.40volt
What is the standard free energy change for the cell reaction of this galvanic cell?
2 answers
It would be more than nice if you didn't switch screen names.
1 answer