Let's analyze the function based on the description you provided.
-
At x = -4: The function has a cusp at the point (-4, 3). A cusp is a point where the function is not continuous, as the left-hand limit and right-hand limit do not match. Therefore, we can conclude:
- The function is not continuous at x = -4, and it does not have a removable discontinuity.
- There is a cusp, but it is not classified as a removable discontinuity.
-
At x = -1: The function has different behaviors around this point.
- There is an open point at (-1, 0) and a closed point at (-1, 0.75). This indicates a jump because the value of the function jumps from 0.75 to the open value of 0 at x = -1. The function does not take the value of 0 at that point.
- Therefore, we can conclude that there is a jump discontinuity at x = -1.
Considering the analysis above, we can summarize the continuity of the function as follows:
- The function is not continuous at x = -4 (due to the cusp).
- The function has a jump discontinuity at x = -1.
So the correct responses from your options will be:
- The function has a jump discontinuity at x = -1.