f(t) = √4t
f(t+h) = √4(t+h)
f(9) = √36 = 6
√(9+h) = √(36t+4h)
avg rate of change is (√(36t+4h) - 6)/h
A function is given below. Determine the average rate of change of the function between
t = 9
and
t = 9 + h.
f(t) =
Square root of 4t
1 answer
1 answer