a. f is increasing where f' > 0
So, where do you have e^sinx-2cos3x > 0 ?
b. you need e^sinx-2cos3x = 0
c. points of inflection are where f" = 0
f" = (e^sinx)(cosx) + 6sin3x
so, where is that zero?
you can check your answers at wolframalpha.com
The graph of e^sinx-2cos3x on [0,4] can be seen at
https://www.wolframalpha.com/input/?i=e%5Esinx-2cos3x+where+0+%3C%3D+x+%3C%3D+4
A function f is defined on the interval [0,4], and its derivative is e^sinx-2cos3x
a. on what interval is f increasing?
b. at what value(s) of x does f have a local maxima?
c. how many points of inflection does f have?
*calculator is allowed for this problem
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