0.5 m V^2 = 0.5*(1/m)*(mV)^2
Kinetic energy = ( 0.5)*(1/m)*(momentum)^2
1 = (1/m)*0.125
m = 0.125 kg
A frog is jumping around its pond. At some time t , the frog is in mid-jump and has a kinetic energy of 1 J and a momentum of magnitude 0.5 kg⋅m/s . What is the mass of the frog in kg?
1 answer