A frog in a hemispherical bowl, as shown below, just floats in a fluid with a density of 1.26*10e3 kg/m3. If the bowl has a radius of 6.16 cm and negligible mass, what is the mass of the frog?

9 answers

Buoyant force= weight of floating object
density of liquid * volume of liquid * gravity=weight
weight = mass*gravity
1350*.4524*9.81=5991.3594=weight
5991.3594/9.8= mass
mass=610.74 N
why would the frog do that
The answer should be
1260 * 2/3*Pi*.0616^3 * 1000 grams

or more simply
1.26 * 2/3 * Pi * 6.16^3 = 616.84 grams
Volume of hemisphere equation: (2/3)(Pi)*radius^3
Remember to convert the radius from centimeters to meters ^
Formula:
(Density of liquid)(Volume of hemisphere)(Gravity) = Buoyancy Force

(1260kg/m^3)(.000490m)(9.8m/s^2) = 6.05kg
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