(65-16)km/hr / 10min
= 4.9 (km/hr)/min
now, 1 km/hr = 1000m/3600s, so now you have
(4.9 * 1000/3600 m/s) / 60s
= 4.9*1000 / 60*3600 m/s^2
a freight train must approach a road crossing at 16km/h. after passing through the intersection, the train speeds up to 65 km/h, taking 10 min to do so. what is the train's acceleration during this time in meters per second squared
2 answers
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