A force vector f1 has a magnitude of 50 north it makes a 45 degree angle with a positive x axis. F2 has a magnitude of 70 north and points straight down. Determine the vector that results from adding f1 and f2
4 answers
are "north" and "down" related to the x,y,z axes?
I think?
I’m not sure. I just started this course. I think so. Do you know how to solve it or get it started?
ok - I think "north" is a typo, maybe for Newtons
That means that
F1 = 50 cos45° i + 50sin45° j = 35.35i + 35.35j
F2 = -70j
So F1+F2 = 35.35i - 34.65j
Now, that's almost the same as 35.35i - 35.35j
which would be 50N at an angle of -45° to the x-axis.
To be more exact, it would be
50/√2 i + (50/√2 - 70)j or
49.50N at an angle of θ where
tanθ = (50/√2 - 70) / (50/√2) = -0.9799
θ = -44.418°
That means that
F1 = 50 cos45° i + 50sin45° j = 35.35i + 35.35j
F2 = -70j
So F1+F2 = 35.35i - 34.65j
Now, that's almost the same as 35.35i - 35.35j
which would be 50N at an angle of -45° to the x-axis.
To be more exact, it would be
50/√2 i + (50/√2 - 70)j or
49.50N at an angle of θ where
tanθ = (50/√2 - 70) / (50/√2) = -0.9799
θ = -44.418°
1 answer