A force of magnitude Fx acting in the x-direction on a 2.55-kg particle varies in time as shown in the figure below. (Indicate the direction with the sign of your answer.)

Question

(a) Find the impulse of the force. (Give your answer to one decimal place.)
kg · m/s

(b) Find the final velocity of the particle if it is initially at rest.
m/s

(c) Find the final velocity of the particle if it is initially moving along the x-axis with a velocity of
−2.10 m/s.

m/s

Answer 1

I can not see your graph but use the logic from the other problem I just helped you with.
F = m a = m dv/dt

impulse = integral F dt = final mv - initial m v

Answer 2

swag