a force of 890n acts on a body that weighs 265n if the body starts from rest, how fast will it be going after it has moved 3.00m

Answer 1

a = F/m = 890/265

d = 0 + 0 + (1/2) a t^2

3 = (1/2)(890/265) t^2
solve for t

v = 0 + a t

v = (890/265) t